Mind Twister Maths Questions: Puzzles and Brain Teasers

Mind Twister Maths Questions: Puzzles and Brain Teasers

There are endless possibilities with which mathematical mind twisters can be made by using only basic mathematical operations of addition, multiplication, division, and subtraction. Adding some more mathematical operations add fun to these math twisters. In these mind-twister questions of math for the first two riddles some of the additional rules as used. However, most of the remaining math riddles can be solved with the basic knowledge of mathematics.

Math riddles in this post are ranging from easy to medium with few exceptions of hard questions. So everyone from kids to high-class math students will enjoy these mind-twister questions. Please write your answers in the comment sections of this post. Let us see how many you can solve without looking for any help :)

In the following two questions, you can use +, -, /, x, square, square root, cube, and cube roots to find the answers. Each given digit is to be used only once.
Q1. How will you get 6 using only digits 5, 3, 3, and 3?

Q2. How will you get 36 by using only the digits 8, 8, 3, and 3?

Q3. IF 0002 = 23
           005  = 52
          00006 = 64
then    00012 = ?

Q4. Find  3 + 3 / 3 x 2 - 5 = ?

Q5. Follow the pattern and complete the Series
     IF WE = 28, ARE = 24 then PUZZLER = ?

Q6. Find the missing number using the given pattern
 2, 5, 11, 23, ____, ______, 191, ____,

Q7. IF  24 x 3 = 18
            36 x 2 = 18
      Then 12 x ___ = 18

Q8. Find what comes next in the Series?
     IN, MR, LQ, _____, _______

Q9. If 1327 = 13
       2368 = 34
       5723 = 29
      5063 = _____
and 3890 = _____

Q10. IF   5 + 6 = 111
           6 + 7  = 113
           7 + 8 = 115
Then    8 + 9 = ?


The Answers to Mind Twister Math Questions

A1.  6
We have to use 5,3,3,3 to get 6
So applying mathematical operations we get,
             5x3- 3x3= 15-9=6


A2. 36
We have to use 8,8,3,3 to get 36
The cube root of 8 = 2, so using the cube root for both 8 we have 2x2x3x3=36.



A3. 123
Explanation:
Its last digit and the next digit are the numbers of zeros.



A4.  0,
using DMAS
3÷3=1X2=2+3=5-5=0



A5.  125
PATTERN IS  WE= place value of W+ place value of E= 23+5=28,
ARE = 1+18+5= 24, PUZZLER= 16+21+26+26+13+5+18=125



A6. 47,95,383
23X2+1=47, 47X2+1=95, 191X2=1=383,



A7) 6
24X3=18  is as below :
2+4=6 x 3=18,  36x2=18 as 3+6=9x2=18, similarly  12=1+2=3x6=18.



A8)      I  N,     M    R,     Q   V,    U    Z,   Y     D
           9  14 ,    13   18,    17  22,   21  26,  25    4
The first alphabet is the place value of the first alphabet of the last term +4, second alphabet= place value of the second alphabet of the last term + 4



A9.   15, 72
Required number= first digit x last digit + second digit x third digit


A10. 117,  required number=  1 and sum of digits
Example  5+6 = 111


4 comments:

Anonymous said...

Q9 is wrong. Example shows 1327=12. Should be 13
(F*L) + (M1*M2) = answer First, last, middle 1, middle 2

(1*7)+ (3*2)= answer
7+6=13. Not 12


Rajesh Kumar said...

You are right. It should be 13. I have updated this puzzle now. Thanks for pointing it out and helping us to improve this website.


Pibou10 said...

A5 should be 124 and not 125. P=16, U=21, Z=26, Z=26, L=12(NOT 13), E=5, R=18
TOTAL 124


Pibou10 said...

A8 contains an error: Original= IN, MR, LQ, ____, _____.
You indicated: IN, MR, QV . . .
I think that the answer is:
IN MR LQ PU TY
9-14 13-18 12-17 16-21 20-25

Thank you and best regards.